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(-F)=4F^2+2F-4
We move all terms to the left:
(-F)-(4F^2+2F-4)=0
We add all the numbers together, and all the variables
(-1F)-(4F^2+2F-4)=0
We get rid of parentheses
-4F^2-1F-2F+4=0
We add all the numbers together, and all the variables
-4F^2-3F+4=0
a = -4; b = -3; c = +4;
Δ = b2-4ac
Δ = -32-4·(-4)·4
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{73}}{2*-4}=\frac{3-\sqrt{73}}{-8} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{73}}{2*-4}=\frac{3+\sqrt{73}}{-8} $
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